Find the position of the final image after three successive reflections taking the first reflection on `m_(1)` .

Explanation

`1^(st)` reflection at `m_(1)`
`u = -15cm`
`f = -10cm`
`(1)/(v) + (1)/(u) = (1)/(f) = (-3+2)/(30) = -(1)/(30)`
`v = -30cm`
`2^(nd)` reflection at plane mirror:
`u = 5cm`
`v = -5cm`
For `III` reflection on curved mirror again:
`u = -20cm`
`v = (uf)/(u-f) = ((-20)xx(-10))/(-20+10) = (200)/(-10) = 20cm`
Image is `20cm` right of `m_(1)`