The view in the figure is form above a plane mirror suspended by a thread connected to the centre of the mirror at a point `A`. A scale is located `0.75m` (the distance form point `A` to point `P`) to the right of the centre fo the mirror. Initially, the palne of the mirror is parallel to the side fo the scale, and the angle of incidence of a light ray which is directed at the centre of the mirror is `30^(@)`. A small torque appleid to the thread causes the mirror to turn `11.5^(@)` away form its initial positon. The reflected ray then intersects the scale at point `Q`.
The distance form point `P` to point `Q` on the scale is

Options

A. `1.00m`
B. `0.56m`
C. `1.02m`
D. `0.86m`

Answer

A

Explanation

`tan (11.5+41.5)^(@)`
`= tan 53^(@) = (PQ)/(0.75) rArr PQ = (4)/(3) xx 0.75 = 1m`