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The sun subtends an angle of (1//2)^(@) ...

The sun subtends an angle of `(1//2)^(@)` on earth. The image of sun is obtained on the screen with the help of a convex lens of focal length 100 cm the diameter of the image obtained on the screen will be

A

`1`

B

`3`

C

`5`

D

`9`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the diameter of the image of the sun formed by a convex lens. The sun subtends an angle of \( \frac{1}{2}^\circ \) at the earth, and the focal length of the lens is given as 100 cm. ### Step-by-Step Solution: 1. **Convert the angle from degrees to radians**: \[ \theta = \frac{1}{2}^\circ = \frac{1}{2} \times \frac{\pi}{180} \text{ radians} \] \[ \theta = \frac{\pi}{360} \text{ radians} \] 2. **Use the formula for the diameter of the image**: The diameter of the image \( x \) formed by the lens can be calculated using the formula: \[ x = f \cdot \theta \] where \( f \) is the focal length of the lens. 3. **Substitute the values into the formula**: Given that the focal length \( f = 100 \text{ cm} \), we can substitute: \[ x = 100 \cdot \frac{\pi}{360} \] 4. **Calculate the value of \( x \)**: \[ x = \frac{100\pi}{360} = \frac{100\pi}{360} = \frac{5\pi}{18} \text{ cm} \] To get a numerical approximation, we can use \( \pi \approx 3.14 \): \[ x \approx \frac{5 \times 3.14}{18} \approx \frac{15.7}{18} \approx 0.872 \text{ cm} \] 5. **Convert to centimeters**: Since the diameter is usually expressed in centimeters, we can round our answer: \[ x \approx 0.872 \text{ cm} \approx 0.89 \text{ cm} \] 6. **Final answer**: The diameter of the image of the sun obtained on the screen is approximately \( 0.89 \text{ cm} \).

To solve the problem, we need to find the diameter of the image of the sun formed by a convex lens. The sun subtends an angle of \( \frac{1}{2}^\circ \) at the earth, and the focal length of the lens is given as 100 cm. ### Step-by-Step Solution: 1. **Convert the angle from degrees to radians**: \[ \theta = \frac{1}{2}^\circ = \frac{1}{2} \times \frac{\pi}{180} \text{ radians} \] ...
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RESONANCE ENGLISH-GEOMATRICAL OPTICS -Exercise-1
  1. When a lens of power P (in air) made of material of refractive index m...

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  2. A lens behaves as a converging lens in air and a diverging lens in wat...

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  3. The sun subtends an angle of (1//2)^(@) on earth. The image of sun is ...

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  4. A lens having focal length f and aperture of diameter d forms an image...

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  5. A thin symmetrical double convex lens of power P is cut into three par...

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  6. In the figure shown, there are two convex lenses L(1) and L(2) having ...

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  7. An object is placed at a distance u from a concave mirror and its real...

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  8. A real inverted image in a concave mirror represented by graph (u, v, ...

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  9. What should be the value of distance d so that final image is formed o...

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  10. An object is kept on the principal axis of a concave mirror of focal l...

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  11. A biconvex lens is used to project a slide on screen. The slide is 2 c...

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  12. The minimum distance between a real object and its real image formed b...

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  13. Two planoconvex lenses each of the focal length of10cm&refractive inde...

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  14. A plano-convex lens when silvered in the plane side behaves like a con...

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  15. Define: Radius of curvature and centre of curvature

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  16. The focal length of a plano-concave lens is -10 cm , then its focal le...

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  17. A convex lens of focal length 80 cm and a concave lens of focal length...

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  18. The dispersion of light in a medium implies that :

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  19. Critical angle of light passing from glass to air is least for

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  20. A plane glass slab is placed over various coloured letters. The letter...

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