A real inverted image in a concave mirror represented by graph (u, v, f are coordinates)

Options

A.
B.
C.
D.

Answer

B

Explanation

For vertical erect image by diverging lens.
`u`, `v` and `f` are negative
`therefore (u)/(f)=+ve` and `(v)/(f)=+ve`
`(1)/(f)=(1)/(v)-(1)/(u) 1=(f)/(v)-(f)/(u) (1)/(y)=(1)/(x)+1`
`y=(x)/(x+1)` since `x & y` and `+ve` graph lies in firstt quadrant. Also, at `x=0,y=0` and at `x=infty ,, y=1` Hence, `(D)`