The refractive index of a glass is 1.520 for red light and 1.525 for blue light. Let `D_1` and `D_2` be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then,

Options

A. `D_(1)` can be less than or greater than `D_(2)` depending upon the angle of prism
B. `D_(1)gtD_(2)`
C. `D_(1)ltD_(2)`
D. `D_(1)=D_(2)`

Explanation

To solve the problem, we need to analyze the relationship between the refractive indices of the glass for red and blue light and their corresponding angles of minimum deviation in a prism.

### Step-by-step Solution:

1. **Understanding Refractive Index**:
- The refractive index (μ) of a medium varies with the wavelength of light. In this case, we have:
- μ (red light) = 1.520
- μ (blue light) = 1.525

2. **Minimum Deviation Formula**:
- The angle of minimum deviation (D) for a prism is related to the refractive index by the formula:
\[ D = μ - 1 \cdot A \]
- Here, A is the angle of the prism, which is constant for both colors of light.

3. **Comparing Refractive Indices**:
- Since μ (blue light) = 1.525 and μ (red light) = 1.520, we can see that:
\[ μ_{blue} > μ_{red} \]

4. **Relation Between Minimum Deviation and Refractive Index**:
- The angle of minimum deviation is directly proportional to the refractive index. Therefore:
\[ D_2 > D_1 \]
- This means that the minimum deviation for blue light (D2) is greater than that for red light (D1).

5. **Conclusion**:
- From the above analysis, we conclude that:
\[ D_2 > D_1 \]
- Hence, the correct option is C, which states that the angle of minimum deviation for blue light is greater than that for red light.