Two monochromatic ray of light are incident normally on the face AB of an isosceles right - angled 'I' and '2' are respectively 1.35 and 1.45. Trace path of these rays after entering through the prism.

Explanation

(1) `mu_(1)=1.38`
for critical angle
`Sin C_(1)=1//mu_(1)`
`Sin C_(1)=1//1.38`
for both rays angle of incidence is `45^(@)`
`sin C_(1)=(1)/(1.38)` .
`C_(1)gt45^(@)(46.44^(@))`
Thus, second ray will go for `T.I.R.`
(2) `mu_(2)=1.52`
for critical angle
`Sin C_(2)=1//mu_(2)`
`Sin C_(2)=1//1.52`
`Sin C_(2)=(1)/(1.52)`
`C_(2)lt45^(@)(41-14^(@))`