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A point source is at a distance 35cm on...

A point source is at a distance `35cm` on the optical axos from a spherical mirror having a focal length `25cm`. At what distance measured along the optical axis form the concave mirror should a plane mirror (perpendicualr to principle axis) be placed for the image it forms (due to rays falling on it after reflection from the concave mirror) to coincide with the point source?

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To solve the problem step by step, we will use the mirror formula and the properties of image formation by mirrors. ### Step 1: Identify the given values - Distance of the point source from the concave mirror (u) = -35 cm (negative because it is measured against the direction of incident light) - Focal length of the concave mirror (f) = -25 cm (negative for concave mirrors) ### Step 2: Use the mirror formula The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] where: - \( f \) = focal length of the mirror - \( v \) = image distance from the mirror - \( u \) = object distance from the mirror Substituting the known values into the formula: \[ \frac{1}{-25} = \frac{1}{v} + \frac{1}{-35} \] ### Step 3: Rearranging the equation Rearranging the equation gives: \[ \frac{1}{v} = \frac{1}{-25} + \frac{1}{35} \] ### Step 4: Finding a common denominator The common denominator for -25 and 35 is 175. Therefore, we can rewrite the equation: \[ \frac{1}{v} = \frac{-7}{175} + \frac{5}{175} = \frac{-7 + 5}{175} = \frac{-2}{175} \] ### Step 5: Calculate the image distance (v) Now, we can find \( v \): \[ v = \frac{175}{-2} = -87.5 \text{ cm} \] (The negative sign indicates that the image is formed on the same side as the object, which is typical for a concave mirror.) ### Step 6: Determine the distance between the image and the object Now, we need to find the distance between the object and the image: - Distance from the object to the image = \( |u| + |v| = 35 + 87.5 = 122.5 \text{ cm} \) ### Step 7: Positioning the plane mirror For the image formed by the plane mirror to coincide with the point source, the plane mirror must be placed halfway between the object and the image. Thus: \[ \text{Distance from the concave mirror to the plane mirror} = \frac{122.5}{2} = 61.25 \text{ cm} \] ### Step 8: Calculate the final position of the plane mirror Since the image is formed at 87.5 cm from the concave mirror, we can find the position of the plane mirror: \[ \text{Distance from the concave mirror to the plane mirror} = 87.5 - 61.25 = 26.25 \text{ cm} \] Thus, the distance from the concave mirror to the plane mirror is: \[ 35 + 26.25 = 61.25 \text{ cm} \] ### Final Answer The plane mirror should be placed at a distance of **61.25 cm** from the concave mirror along the optical axis. ---

To solve the problem step by step, we will use the mirror formula and the properties of image formation by mirrors. ### Step 1: Identify the given values - Distance of the point source from the concave mirror (u) = -35 cm (negative because it is measured against the direction of incident light) - Focal length of the concave mirror (f) = -25 cm (negative for concave mirrors) ### Step 2: Use the mirror formula The mirror formula is given by: ...
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RESONANCE ENGLISH-GEOMATRICAL OPTICS -Exercise-1
  1. A point object is placed (0,0) and a plane mirror 'M' is placed, incl...

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  2. A rod of length 10 cm lies along the principal axis of a concave mirr...

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  3. A point source is at a distance 35cm on the optical axos from a sph...

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  4. Find the diameter of the image of the moon formed by a spherical conc...

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  5. The radius of curvature of a convex spherical mirror is 1.2m. How fa...

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  6. A converging beam of light rays in incident on a concave spherical ...

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  7. A point object is placed on the principle axis at 60cm in fornt ...

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  8. A man uses a concave mirror for shaving. He keeps his face at a dist...

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  9. Two spherical mirros (convex and concave) having the same focal leng...

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  10. A light ray falling at an angle of 45^@ with the surface of a clean sl...

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  11. A light ray is incident at 45^(@) on a glass slab. The slab is 3cm thi...

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  12. In the given figure an abserve in air (n=1) sees the botoom of a bre...

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  13. In the given figure rasy incident on an interface would converge 10c...

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  14. A fish is rising up veritcally inside a pond with velocity 4 m//s, and...

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  15. Find the apparednt distance between the observer and the object shwon ...

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  16. Find the apparent depth of object of the object seen by observe A (in...

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  17. Locate the image fo the point P as seen by the eye in the figure.

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  18. A small object is placed at the centre of the bottom of a cylindrical ...

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  19. A point source is placed at a depth h below the surface of water (re...

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  20. Light falls from glass (mu=1.5) to air. Find the angle of incidence fo...

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