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A charged particle has acceleration veca...

A charged particle has acceleration `veca=2hati+xhatj` in a magnetic field `vecB=-3hati+2hatj-4hatk`.Find the value of `x`.

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`vecF=qvecvxxvecB=(2xx10(2-3)xx4k) = 2xx10^(-5)(-6j+4hati+6hatk)N`
By Newton's law `veca=F/m=(2xx10^(-5))/(5xx10^(-5))(-6hati+4hatj+6hatk)`
`=0.8 (-3hati+2hatj+3hatk)m//s^(2)`
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