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In the above question, the angular veloc...

In the above question, the angular velocity will:

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(i)`2pi-2theta=2pi-2.pi/6=2pi-pi/3=(5pi)/3`
`=omegat=(qBt)/m rArr t=(5pim)/(3qB)`
(ii)Distance travelled `s=r(2pi-2theta)=(5pir)/3`
(iii)Impulse =charge in linear momentum
`=m(-v sin thetahati+v cos thetahatj)-m(v sin thetahati+v cos theta hatj)`
`=-2mv sinthetahati=-2mv sin (pi/6)hati=-mv hati`
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