Two parallel wires in the plane of the paper are distance `x_(0)` apart. A point charge is moving with speed u between the wires in the same plane at a distance `x_(1)` from one of the wires. When the wires carry current of magnitude I in the same direction, the radius of curvature of the path of the point charge is `R_(1)`. In contrast, if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is `R_(2)`. if `(x_(0))/(x_(1))=3`, and value of `(R_(1))/(R_(2)) square` .

Answer

3

Explanation

`B_(2)=(mu_(0)l)/(2pix_(1))+(mu_(0)l)/(2pi(x-x_(1)))`(opposite)
`B_(1)=(mu_(0)l)/(2pix_(1))-(mu_(0)l)/(2pi(x-x_(1)))`(same)
Case-I When current is in the same direction
`B=B_(1)=(3mu_(0)l)/(2pix_(0))-(3mu_(0)l)/(4pix_(0))=(3mu_(0)l)/(4pix_(0))rArrR_(1)=(mv)/(qB_(1))`
Case-2 When current is in opposite direction
`B=B_(2)=(9mu_(0)l)/(4pix_(0)) rArr R_(2)=(mv)/(qB_(2)) rArr R_(1)/R_(2)=B_(2)/B_(1)=9/3=3`