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A charged particle of mass m and charge ...

A charged particle of mass m and charge q moves along a circular path of radius r that is perpendicular to a magnetic field B. the time taken by the particle to complete one revolution is

A

`(2pimq)/B`

B

`(2piq^(2))/B`

C

`(2piq^(2)B)/m`

D

`(2pim)/(qB)`

Text Solution

Verified by Experts

The correct Answer is:
4

Magnetic force `F=qupsilonB` …(i)
Centripetal force
`F=(mepsilon^(2))/r`...(ii)
From Eq. (i) and
`(mepsilon^(2))/r=qepsilonB rArrr=(mepsilon)/(qB)`
The time taken by the particle to complete one revolution.
`T=(2pir)/v=(2pimv)/(qB)=(2pim)/(qB)`
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