A current loop ABCD is held fixed on the plane of the paper as shown in the figure. The arcs BC (radius = b) and DA radius = a) of the loop are joined by two straight wires AB and CD. A steady current I is flowing in the loop. Angle made by AB and CD at the origin O is `30^(@)`. Another straight thin wire with steady current `I_(1)` flowing out of the plane of the paper is kept at the origin.

The magnitude of the magnetic filed (B) due to loop ABCD at the origin (O) is :

Options

A. The forces on `AD` and `BC` are zero.
B. The magnitude of the net force on the loop is given by `(mu_(0)I_(1)I)/(4pi)[2(b-a)+pi/3(1+b)]`
C. The magnitude of the net force on the loop is given by `(mu_(0)II_(1))/(24ab)(b-a)`
D. the forces on `AB` and `DC` are zero.

Answer

1

Explanation

Magnetic field due to `l_(1)` is parallel to `AD` and `BC`.So that force On `AD` and `BC` is zero.