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Two long parallel straight wires X and Y separated by a distance `5cm` in air carry currents of `10A` and `5A` respectively in opposite directions. Calculate the magnitude and direction of force on a `20cm` length of the wire Y. Figure

Text Solution

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`F=(mu_(0)I_(1)I_(2)l)/(2pir)=(4pixx10^(-7)xx10xx5xx0.20)/(2pixx0.05)`
`=4xx10^(-5)N`
The direction of the force is perpendicular to the length of wire `Y` and acts away from `X`(repulsion)
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