For the given reaction identify the true (T) & false (F) statements
`C_(2)H_(5)NH_(2)+HIhArr (C_(2)H_(5)NH_(3))^(+)Gamma`
`S_(1):HI` is bronsted base
`S_(2)HI` is bronsted acid
`S_(3):HI` is arrhenius acid
`S_(4):HI` is lewis acid
`S_(5):HI` is arrhenius base
`S_(6):HI` is lewis base.

Options

A. `TFFFT T`
B. `FT T TFF`
C. `FT TFFF`
D. `TFFFTF`

Explanation

To analyze the given reaction and identify the true (T) and false (F) statements regarding HI, let's break down the statements one by one.

### Given Reaction:
\[ C_2H_5NH_2 + HI \rightleftharpoons (C_2H_5NH_3)^+ + I^- \]

### Statements Analysis:

**S1: HI is a Bronsted base.**
- **Analysis:** A Bronsted base is defined as a species that accepts protons (H+ ions). In this reaction, HI donates a proton to C2H5NH2, thus acting as a Bronsted acid, not a base.
- **Conclusion:** **False (F)**

**S2: HI is a Bronsted acid.**
- **Analysis:** A Bronsted acid is a species that donates protons. Since HI donates H+ to C2H5NH2, it fits the definition of a Bronsted acid.
- **Conclusion:** **True (T)**

**S3: HI is an Arrhenius acid.**
- **Analysis:** An Arrhenius acid is a substance that increases the concentration of H+ ions in aqueous solution. HI dissociates in water to produce H+ ions, thus acting as an Arrhenius acid.
- **Conclusion:** **True (T)**

**S4: HI is a Lewis acid.**
- **Analysis:** A Lewis acid is defined as a species that can accept an electron pair. HI does not accept electron pairs; it donates H+ ions. Therefore, it does not act as a Lewis acid.
- **Conclusion:** **False (F)**

**S5: HI is an Arrhenius base.**
- **Analysis:** An Arrhenius base is a substance that increases the concentration of OH- ions in solution. HI does not release OH- ions; it releases H+ ions. Thus, it cannot be classified as an Arrhenius base.
- **Conclusion:** **False (F)**

**S6: HI is a Lewis base.**
- **Analysis:** A Lewis base is a species that can donate an electron pair. HI does not have a lone pair of electrons to donate; therefore, it cannot act as a Lewis base.
- **Conclusion:** **False (F)**

### Summary of Statements:
- S1: F
- S2: T
- S3: T
- S4: F
- S5: F
- S6: F

### Final Answer:
- S1: F
- S2: T
- S3: T
- S4: F
- S5: F
- S6: F