In the above question identify the true (T) and false (F) statement is `Hi` is replaced with `C_(2)H_(5)NH_(2)` in each statement .

Options

A. `TFFFT T`
B. `TFFFFT`
C. `FFT TFF`
D. `FT T TFF`

Explanation

To solve the question, we need to analyze the behavior of the compound \( C_2H_5NH_2 \) (ethylamine) in terms of its acid-base properties. We will evaluate each statement after replacing \( HI \) with \( C_2H_5NH_2 \).

### Step-by-Step Solution:

1. **Identify the Compound**:
The compound we are analyzing is \( C_2H_5NH_2 \) (ethylamine). It is an amine and can act as a base.

2. **Evaluate the Statements**:
We will evaluate each statement based on the properties of \( C_2H_5NH_2 \):

- **Statement 1**: "Bronsted base"
- **Evaluation**: Ethylamine can accept a proton (\( H^+ \)) from an acid, which makes it a Bronsted base.
- **Result**: True (T)

- **Statement 2**: "Bronsted acid"
- **Evaluation**: Ethylamine does not donate protons; hence it is not a Bronsted acid.
- **Result**: False (F)

- **Statement 3**: "Arrhenius acid"
- **Evaluation**: Arrhenius acids produce \( H^+ \) ions in solution. Ethylamine does not do this.
- **Result**: False (F)

- **Statement 4**: "Lewis acid"
- **Evaluation**: Lewis acids accept electron pairs. Ethylamine does not accept electron pairs; it donates them.
- **Result**: False (F)

- **Statement 5**: "Arrhenius base"
- **Evaluation**: Arrhenius bases produce \( OH^- \) ions in solution. Ethylamine does not do this directly.
- **Result**: False (F)

- **Statement 6**: "Lewis base"
- **Evaluation**: Ethylamine can donate a lone pair of electrons to an electron-deficient species, making it a Lewis base.
- **Result**: True (T)

3. **Summary of Results**:
- Statement 1: True (T)
- Statement 2: False (F)
- Statement 3: False (F)
- Statement 4: False (F)
- Statement 5: False (F)
- Statement 6: True (T)

### Final Answer:
- The true (T) and false (F) statements are:
- 1: T
- 2: F
- 3: F
- 4: F
- 5: F
- 6: T