Calcuate `pH` of `10^(-8)M HCl` solution at `25^(@)C` (Take `log1.05=0.02)`

Explanation

To calculate the pH of a \(10^{-8} \, M\) HCl solution at \(25^\circ C\), we need to consider the contribution of hydrogen ions from both the HCl and the water itself. Here’s a step-by-step solution:

### Step 1: Understand the Contribution of HCl
HCl is a strong acid and completely dissociates in water. Therefore, the initial concentration of hydrogen ions \([H^+]\) from HCl is:
\[ [H^+] = 10^{-8} \, M \]

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