Calculate `pH` of mixture of `(400mL,(1)/(200)M Ba(OH)_(2))+(400mL.(1)/(50)M HCl)+(200mL "of water")`

Explanation

To calculate the pH of the mixture of \( (400 \, \text{mL}, \frac{1}{200} \, \text{M} \, \text{Ba(OH)}_2) + (400 \, \text{mL}, \frac{1}{50} \, \text{M} \, \text{HCl}) + (200 \, \text{mL} \, \text{of water}) \), we can follow these steps:

### Step 1: Calculate the moles of Ba(OH)₂ and HCl
1. **Moles of Ba(OH)₂:**
\[ \text{Molarity} = \frac{\text{moles}}{\text{volume (L)}} \]
\[
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