Home
Class 12
CHEMISTRY
Calculate degree of hydrolysis(h) and pH...

Calculate degree of hydrolysis(h) and pH of solution obtained by dissolving `0.1` moles of `CH_(3)COOHNa` in water to get `100L` of solution .Take `K_(a)` of acetic acid `=2xx10^(-5)` at `25^(@)C`.

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the degree of hydrolysis (h) and the pH of a solution obtained by dissolving 0.1 moles of sodium acetate (CH₃COONa) in 100 liters of water. The dissociation constant (Kₐ) for acetic acid is given as 2 × 10^(-5) at 25°C. ### Step-by-step Solution: 1. **Calculate the Concentration of the Solution:** - The concentration (C) of the solution can be calculated using the formula: \[ C = \frac{\text{Number of moles}}{\text{Volume in liters}} ...
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Solved Example Miscellaneous solved problems|13 Videos
  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Board Level Exercise|27 Videos
  • HYDROCARBON

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Hydrocarbon)|50 Videos
  • IUPAC NOMENCLATURE & STRUCTURAL ISOMERISM

    RESONANCE ENGLISH|Exercise Advanced Level Problems Part-5|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the degree of hydrolysis and pH of 0.2M solution of NH_(4)C1 Given K_(b) for NH_(4)OH is 1.8 xx 10^(-5) .

Calculate the degree of hydrolysis of 0.1 M solution of acetate at 298 k. Given : K_a=1.8xx10^(-5)

When 0.1 mole of NH_(3) is dissolved in water to make 1.0 L of solution, the [OH^(-)] of solution is 1.30xx10^(-3)M. Calculate K_(b) for NH_(3).

When 0.1 mole of NH_(3) is dissolved in water to make 1.0 L of solution , the [OH^(-)] of solution is 1.34 xx 10^(-3) M. Calculate K_(b) for NH_(3) .

The pH of solution, containing 0.1N HCl and 0.1N CH_(3)COOH(K_(a)=2xx10^(-5)) is

Find the pH at equivalence points when a soluiton of 0.1M acetic acid is titrated with a solution of 0.3M NaOH K_(a) for acetic acid =7.5xx10^(-6)

The ratio of pH of solution (1) containing 1 mole of CH_(3)COONa and 1 mole of HCl and solution (II) containing 1 mole of CH_(3)COONa and 1 mole of acetic acid in one litre is :

Calculate the pH of a buffer solution containing 0.15 mole of CH_3COOH and 0.1 mole of CH_3 COO Na per litre. The dissociation constant for acetic acid 1.8 xx 10 ^(-5)

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at 298 K : K_(a) = 1.8 xx 10^(-5) .

Calculate the percent hydrolysis of acetic acid in a solution 2.3 M in CH_(3)COOH and 0. 1 in HCl . K_(a) = 1.8 xx10^(-5)