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Calculate the pH of 0.01 M solution of N...

Calculate the pH of 0.01 M solution of `NH_4CN`. The dissociation constant `k_a` for `HCN=6.2 xx 10^(-10) and K_b "for" NH_3=1.6 xx10^(-5)`.

Text Solution

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`pH=(1)/(2)[14+pK_(a)-pK_(b)]=(1)/(2)[14+10-log5-5+log2]=(1)/(2)[18.6]=9.3`
`(h)/(h-1)=sqrt(K_(h))=sqrt((K_(w))/(K_(a)xxK_(b)))=sqrt((10^(-14))/(5xx10^(-16)xx2xx10^(-5)))=1`
`rArr 2h=1`
`rArr h=(1)/(2)=0.5`
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