Home
Class 12
CHEMISTRY
Calculate [H^(+)] in a 0.20M solution of...

Calculate `[H^(+)]` in a `0.20M` solution of dichloriacetic acid `(K_(a)=5xx10^(-2))` that also contains `0.1M` sodium dichloroacetate.Neglect hydrolysis of sodium salt.

Text Solution

AI Generated Solution

To calculate the concentration of hydrogen ions \([H^+]\) in a \(0.20 \, M\) solution of dichloroacetic acid \((CHCl_2COOH)\) with \(0.1 \, M\) sodium dichloroacetate, we can follow these steps: ### Step 1: Write the dissociation equation for dichloroacetic acid Dichloroacetic acid dissociates in water as follows: \[ CHCl_2COOH \rightleftharpoons H^+ + CHCl_2COO^- \] ...
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Solved Example Miscellaneous solved problems|13 Videos
  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Board Level Exercise|27 Videos
  • HYDROCARBON

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Hydrocarbon)|50 Videos
  • IUPAC NOMENCLATURE & STRUCTURAL ISOMERISM

    RESONANCE ENGLISH|Exercise Advanced Level Problems Part-5|2 Videos

Similar Questions

Explore conceptually related problems

Calculate [H^(+)] in a 0.2M solution of dichloriacetic acid (K_(a)=5xx10^(-2)) that also contains 0.05M H_(2)SO_(4) .Report your answer after multiflying it by 4000 .

A solution containing 0.2 mole of dicholoracetice acid (K_(a)=5xx10^(-2)) and0.1 mole sodium dicholoroacetate in one litre solution has [H^(+)] :

The pH of basic buffer mixtures is given by : pH=pK_(a)+log((["Base"])/(["Salt"])) , whereas pH of acidic buffer mixtures is given by: pH= pK_(a)+log((["Salt"])/(["Acid"])) . Addition of little acid or base although shows no appreciable change for all practical purpose, but since the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) change, a slight decrease or increase in pH results in. A solution containing 0.2 mole of dichloroacetic acid (K_(a)=5xx10^(-2)) and 0.1 mole sodium dichloroacetate in one litre solution has [H^(+)] :

Calculate the ratio of sodium formate and formic acid (K_(a)=2xx10^(-4)) in a buffer solution of pH=4.3.

Calculate the degree of hydrolysis of the 0.01 M solution of salt (KF)(Ka(HF)=6.6xx10^(-4)) :-

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at 298 K : K_(a) = 1.8 xx 10^(-5) .

The ionization constant of chloroacetic acid is 1.35xx10^(-3) . What will be the pH of 0.1 M acid and its 0.1M sodium salt solution?

The [H^(+)] of a resulting solution that is 0.01 M acetic acid (K_(a)=1.8xx10^(-5)) and 0.01 M in benzoic acid (K_(a)=6.3xx10^(-5)) :

Calculate the degree of hydrolysis of 0.1 M solution of acetate at 298 k. Given : K_a=1.8xx10^(-5)

The nature of 0.1 M solution of sodium bisulphate is