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What [H(3)O^(o+)] must be maintained in ...

What `[H_(3)O^(o+)]` must be maintained in a saturated `H_(2)S` solution to precipitate `Pb^(2+)` but not `Zn^(2+)` from a solution in which each ions is `0.01M` ? `K_(sp) H_(2)S = 1.1 xx 10^(-22),K_(sp) ZnS = 1.0 xx 10^(-21)`

Text Solution

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For `ZnS` not to be precipitate from a solution of `Zn^(2+)` and `Pb^(2+),IP_(ZnS)ltK_(sp(ZnS))`
`[Zn^(2+)][S^(2-)] ltK_(sp) of ZnS`
`[10^(-2)][S^(2-)] lt1.0xx10^(-21):.[S^(2-)lt10^(-19)M`
so at `[S^(2-)]=10^(-19)M` or less no precipitaion of `ZnS` will occur.
`H_(2)S hArr 2H^(+)+S^(2-)`
`:.[H^(+)]^(2)[S^(2-)]=K_(sp(H_(2)S))=1.1xx10^(-22):.[H^(+)]_(min)^(2)=1.1xx10^(-22)`
`[H^(+)]_(min)^(2)=11xx10^(-4):.[H^(+)]_(min)=3.3xx10^(-22)`
Thus if `[H^(+)=3.3xx10^(-2)M` or more the precipitaion of `ZnS` will not take place and only `PbS` will precipitate .
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