At `-50^(@)C` liquid `NH_(3)` has ionic product is `10^(-30)` .How many amide `(NH_(2)^(-))` ions are present per mm`.^(3)` in pure liqudi `NH_(3)`? (Take `N_(A)=6xx10^(23)`)

Explanation

To solve the problem, we need to determine the concentration of amide ions (NH2^(-)) in pure liquid NH3 at -50°C, given the ionic product (K) of NH3 is 10^(-30).

### Step-by-Step Solution:

1. **Understand the Ionic Product**:
The ionic product (K) of NH3 can be expressed as:
\[
K = [NH_4^+][NH_2^-]
...