What is the ionisation constant of `HOCl` if `K_(b)` of `Ocl^(-)=4xx10^(-10)` ?Also find its `pK_(a)`.

Explanation

To find the ionization constant \( K_a \) of \( HOCl \) given that \( K_b \) of \( OCl^- \) is \( 4 \times 10^{-10} \), we can use the relationship between the ionization constants of conjugate acid-base pairs. The relationship is given by:

\[ K_w = K_a \times K_b \]

where \( K_w \) is the ion product of water at 25°C, which is \( 1.0 \times 10^{-14} \).

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