Acetic acid gets `1.3%` ionised in its decimolar solution.What is be the ionisation constant of acetic acid?

Explanation

To find the ionization constant (Ka) of acetic acid given that it gets 1.3% ionized in a decimolar solution, we can follow these steps:

### Step 1: Determine the initial concentration of acetic acid
A decimolar solution means the concentration of acetic acid (C) is 0.1 M (or \(1 \times 10^{-1}\) M).

### Step 2: Calculate the degree of ionization (α)
The degree of ionization (α) is given as 1.3%. To convert this percentage into a fraction, we divide by 100:
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