Calculate the `pH` of `500mL` Solution of `1 M BOH (K_(b)=2.5xx10^(-5))`

Explanation

To calculate the pH of a 500 mL solution of 1 M BOH (with \( K_b = 2.5 \times 10^{-5} \)), we can follow these steps:

### Step 1: Write the dissociation equation
The dissociation of BOH in water can be represented as:
\[ \text{BOH} \rightleftharpoons \text{B}^+ + \text{OH}^- \]

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