A `0.25 M` solution of pyridinium chloride `C_(5)H_(5)NH^(+)Cl^(-)` was found to have a `pH` of `2.75` What is `K_(b)` for pyridine, `C_(5)H_(5)N`?

Explanation

To find the base dissociation constant \( K_b \) for pyridine from the given information about pyridinium chloride, we can follow these steps:

### Step 1: Understand the Hydrolysis of Pyridinium Chloride
Pyridinium chloride (\( C_5H_5NH^+Cl^- \)) is a salt formed from a weak base (pyridine, \( C_5H_5N \)) and a strong acid (HCl). When dissolved in water, it undergoes hydrolysis:

\[ C_5H_5NH^+ + H_2O \rightleftharpoons C_5H_5N + H_3O^+ \]
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