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For, H(3)PO(4)+H(2)OhArrH(3)O^(+)+H(2)PO...

For, `H_(3)PO_(4)+H_(2)OhArrH_(3)O^(+)+H_(2)PO_(4)^(-), K_(a_(1))`
`H_(2)PO_(4)+H_(2)OhArrH_(3)O^(+)+HPO_(4)^(2-), K_(a_(2))`
`HPO_(4)^(2-)+H_(2)OhArrH_(3)O^(+)+PO_(4)^(3-), K_(a_(3))`
The correct order of `K_(a)` values is:

A

`K_(a_(1))gtK_(a_(2))gtK_(a_(3))`

B

`K_(a_(1))ltK_(a_(2))ltK_(a_(3))`

C

`K_(a_(1))gtK_(a_(2))gtK_(a_(3))`

D

`K_(a_(1))ltK_(a_(2))gtK_(a_(3))`

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For each weak polyprotic acid `K_(a_(1))gtK_(a_(2))gtK_(a_(3))`.......
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H_(3)PO_(4)hArr H^(o+) +H_(2)PO_(4)^(Theta), K_(a_(1)) : H_(2)PO_(4)^(Theta) hArr H^(o+) +HPO_(4)^(2-),' K_(a_(2)) : HPO_(4)^(2-) hArr H^(o+) + PO_(4)^(3-), K_(a_(3)): Mark out the incorrect statements:

For H_(3)PO_(4) , H_(3)PO_(4) rarr H_(2)PO_(4)^(-)+H^(+)(K_(1)), H_(2)PO_(4)^- rarr HPO_(4)^(-)+H^(+) (K_2), HPO_(4)^(2-) rarr PO_(4)^(3-) + H^(+) (K_(3)) then

H_(3)PO_(4)+H_(2) Leftrightarrow H_(3)O^(+)+H_(2)PO_(4)^(-),pK_(1)=2.15 H_3PO_(4)^(-)+H_(2)O Leftrightarrow H_(3)O^(+)+HPO_(4)^(2-), pK_(2)=7.20 Hence pH of 0.01 M NaH_(2)PO_(4) is

H_(3)PO_(2)+AgNO_(2) to Ag darr+H_(3)PO_(4)+NO

H_(3)PO_(2)+AgNO_(2) to Ag darr+H_(3)PO_(4)+NO

The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan) , unit of K_(c)=(mol L^(-1))^(Deltan) H_(3)ClO_(4) is a tribasic acid, it undergoes ionisation as H_(3)ClO_(4) hArr H^(o+)+H_(2)ClO_(4)^(-), K_(1) H_(2)ClO_(4)^(-) hArr H^(o+)+HClO_(4)^(2-), K_(2) HClO_(4)^(2-) hArr H^(o+)+ClO_(4)^(3-), K_(3) Then, equilibrium constant for the following reaction will be: H_(3)ClO_(4) hArr 3H^(o+)+ClO_(4)^(3-)

H_(3)underline(P)O_(5)+H_(2)O to H_(3)PO_(4)+H_(2)O_(2)

H_(3)underline(P)O_(5)+H_(2)O to H_(3)PO_(4)+H_(2)O_(2)

Three reactions involving H_(2)PO_(4)^(-) are given below I. H_(3)PO_(4)+H_(2)OrarrH_(3)O^(+)+H_(2)PO_(4)^(-) II. H_(2)PO_(4)^(-)+H_(2)OrarrHPO_(4)^(2-)+H_(3)O^(+) III. H_(2)PO_(4)^(-)+OH^(-)rarrH_(3)PO_(4)+O^(2-) In which of the above does H_(2)PO_(4)^(-) act as an acid?

H_(4)underline(P_(2))O_(7)+H_(2)O to 2H_(3)PO_(4)

RESONANCE ENGLISH-IONIC EQUILIBRIUM-Part -II (only one option correct type)
  1. K(a) for monobasic acid ,whose 0.1M solution has pH of 4.5 is :

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  2. For 10^(-4) M BOH (weak base) ,K(b)=5xx10^(-5)):

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  3. For, H(3)PO(4)+H(2)OhArrH(3)O^(+)+H(2)PO(4)^(-), K(a(1)) H(2)PO(4)+H...

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  4. 6 gm of acetic acid are present in a 200 litre aqueous solution . If ...

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  5. In a solution of 0.1M H(3)PO(4) acid (Given K(a(1))=10^(-3),K(a(2))=10...

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  6. In a solution of 0.1M H(3)PO(4) acid Given K(a(1))=10^(-3),K(a(2))=10^...

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  7. pH = 7.4 , K1 of H2CO3 = 4.5 X 10^(-7) . What will be the ratio of [HC...

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  8. In a solution of 0.1M H(3)PO(4) acid (Given K(a(1))=10^(-3),K(a(2))=10...

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  9. Generally in aqueous solutions of weak polyacidic bases ,OH^(-) ions p...

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  10. In a 0.2M aqueous solution of Ethylene diamine (H(2)NCH(2)CH(2)NH(2)):...

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  11. The dissociation constant of acetic acid at a given temperature is 1.6...

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  12. On adding 100mL of 10^(-2) M NaOH solution to 100mL of 0.01M Triethyl ...

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  13. On addition of 100mL 0.01 M of NaOH solultion to 100mL 0.01M triethy...

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  14. Consider an aqueous solution 0.1 M each in HOCN, HCOOH, (COOH)2 and H3...

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  15. What are [H^(o+)], [A^(Theta), and [B^(Theta)] in a solution that is 0...

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  16. pH of solution obtained by mixing equal volumes of 0.1M Triethyl amine...

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  17. In a solution containing 0.1M HCl & 0.1M H(3)PO(4) (having dissociatio...

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  18. calculate the solubility of PbBr2. Solubility product constant for PbB...

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  19. For a solution obtained by mixing equal volumes of 0.02M KOH solution ...

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  20. A pair of salts are given in a solution each is 0.1 M in concentration...

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