`pH` of solution obtained by mixing equal volumes of `0.1M` Triethyl amine `(K_(b)=6.4xx10^(-5))` & `(4)/(45)M NH_(4)OH (K_(b)=1.8xx10^(-5))` will be :

Options

A. `11.3`
B. `10.3`
C. `12.3`
D. `11.45`

Explanation

To find the pH of the solution obtained by mixing equal volumes of 0.1 M triethylamine and (4/45) M NH₄OH, we can follow these steps:

### Step 1: Determine the concentrations after mixing
When equal volumes of two solutions are mixed, the concentration of each solute will be halved.

- Concentration of triethylamine after mixing:
\[
C_1 = 0.1 \, \text{M} \times \frac{1}{2} = 0.05 \, \text{M}
...