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Calculate the ratio of concentration of ...

Calculate the ratio of concentration of `HCOO^(-) & OCN^(-)` ions in a solution containing `0.1M HCOOH (K_(a)=1.8xx10^(-4))` and `0.1M HOCN(K_(a_(1))=4xx10^(-4))` .if simplest ratio is `a:b` reprot your answer as `(a+b)`.

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Verified by Experts

`[H^(+)]` is the same for equilibria of both acids.
Now ,let `[HCOO^(-)]=aM` and `[OCN^(-)]=b M`
`:.([H^(+)]xxa)/(0.1)=1.8xx10^(-4)&([H^(+)]xxb)/(0.1)=4xx10^(-4)rArr (a)/(b)=(9)/(20)` So `(a+b)=29`
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