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pH calculation upon dilute of strong aci...

`pH` calculation upon dilute of strong acid solution is generally done by equating `n_(H)` in original solution & diluted solution.However . If strong acid solution is very dilute then `H^(+)` from water are also to be considered take `log3.7=0.568` and answer the following questions.
A `1` litre solution of `pH=6` (solution of a strong acid) is added to the `7//3` litres of water.What is the `pH` of resulting solution? Neglect the common ion effect on `H_(2)O`.

A

`6.4`

B

`6.52`

C

`6.365`

D

`6.432`

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the pH of the resulting solution after diluting a strong acid solution with water. Here’s a step-by-step breakdown of the solution: ### Step 1: Determine the concentration of H⁺ ions in the original solution The pH of the original strong acid solution is given as 6. We can calculate the concentration of H⁺ ions using the formula: \[ [H^+] = 10^{-\text{pH}} = 10^{-6} \, \text{mol/L} \] ...
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pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litres solution of pH=4 (solution of a strong acid ) is added to the 7//3 litres of water.What is the pH of resulting solution?

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