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Calculate the pH of a given mixtures. ...

Calculate the pH of a given mixtures.
(a) `(4g CH_(3)COOH+6g CH_(3)COONa)` in 100 mL of mixture, (`K_(a)` for `CH_(3)COOH=1.8xx10^(-5))`
(b) 5 mL of `0.1M MOH+250` mL of `0.1 M MCI`, (`K_(b)` for `MOH=1.8xx10^(-5))`
(c ) (`0.25` mole of `CH_(3)COOH+0.35` mole of `CH_(3COOH=3.6xx10^(-4))`

Text Solution

Verified by Experts

`pH=-logK_(a)+log(([CH_(3)COO^(-)])/([CH_(3)COOH]))`
`:. pH=-log1.8xx10^(-5)+log((4.1xx60)/(82xx4))=4.74+log((3)/(2))=4.62`
`(b) pOH=-logK_(b)+log(([B^(+)])/([BOH]))`
`:.pOH=-log1.8xx10^(-5)+log((2.5)/(0.5))=4.74+log5=5.44`
`:.pH=14-pOH=8.56`
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