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A 0.252g sample of unknown organic base ...

A `0.252g` sample of unknown organic base is dissolved in water and titrated with a `0.14 M HCl` solution .After then addition of `20mL` of acid ,a `pH` of `10.7` is recorded. The equivalence point is reached when a total of `40mL` of `HCl` is added . What is the molar mass of the base?

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To find the molar mass of the unknown organic base, we can follow these steps: ### Step 1: Understand the relationship at the equivalence point At the equivalence point of a titration, the number of equivalents of the acid equals the number of equivalents of the base. We can express this relationship mathematically as: \[ \text{Number of milliequivalents of base} = \text{Number of milliequivalents of acid} \] ...
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