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Aniline behaves as a weak base. When 0.1...

Aniline behaves as a weak base. When `0.1M ,50mL` solution sample of aniline was mixed with `0.2 M ,12.5mL` of solution of `HCl` ,the `pH` of resulting solution was `8`.Then `pH` of `0.01 M` solution of anillinium chloride is :

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To solve the problem step by step, we will follow the reasoning laid out in the video transcript. ### Step 1: Calculate the number of millimoles of aniline and HCl 1. **Aniline**: - Molarity (C) = 0.1 M - Volume (V) = 50 mL - Millimoles of aniline = C × V = 0.1 mol/L × 50 mL = 5 mmol ...
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