Home
Class 12
CHEMISTRY
The volume of 0.2 M NaOH needed to prepa...

The volume of `0.2 M NaOH` needed to prepare a buffer of `pH 4.74` with `50 mL` fo `0.2M` acetic acid `(pK_(b) ` of `CH_(3)COO^(-)=9.26)` is `:`

A

`50mL`

B

`25mL`

C

`20mL`

D

`10mL`

Text Solution

Verified by Experts

Let `VmL` of `NaOH` be needed to give `CH_(3)COONa`
`{:(NaOH,+,CH_(3)COOH,rarr,CH_(3)COONa,+,H_(2)O,),(0.2xxV,,50xx0.2,,0,,0,),(-,,[10-0.2V],,0.2V,,0.2V,):}`
`:.pH=pK_(a)+(log)(["Salt"])/(["Acid"])=pK_(w)-pK_(b)+(log)(["Salt"])/(["Acid"])=14-9.26+(log)(["Salt"])/(["Acid"])`
`=14-9.26+(log)(["Salt"])/(["Acid"])=pK_(w)-pK_(b)+(log)(["Salt"])/(["Acid"])=14-9.26+(log)([(0.2V)/(50+V)])/([(10-0.2V)/(50+V)]`
`4.74=4.74+log[(0.2V)/(10-2V)]:.V=(10)/(0.4)=25mL`.
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise -3 part -1|4 Videos

  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise -3 part-2 JEE main|12 Videos

  • IONIC EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Part III One or more than one option correct type|16 Videos

  • HYDROCARBON

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Hydrocarbon)|50 Videos

  • IUPAC NOMENCLATURE & STRUCTURAL ISOMERISM

    RESONANCE ENGLISH|Exercise Advanced Level Problems Part-5|2 Videos

Similar Questions

Explore conceptually related problems

The volume of 0.2 M NaOH needed to prepare a buffer of pH 4.74 with 50 mL fo 0.2M sodium dicholoroacetate acid (pK_(b) of CH_(3)COO^(-)=9.26) is :

pH of 0.005 M calcium acetate (pK_a" of " CH_3COOH= 4.74) is

The volume of 0.1 M Ca (OH)_(2) needed for the neutralization of 40 ml of 0.05 M oxalic acid is

To prepare a buffer solution of pH=4.04, amount of Barium acetate to be added to 100 mL of 0.1 M acetic acid solution [pK_b(CH_(3)COO^(-))=9.26] is:

What volume of 0.2 M NaOH solution is needed for complete neutralisation of 0.49 gm orthophosphoric acid

What is the pH of a 0.50M aqueous NaCN solution ? (pK_(b)of CN^(-)=4.70)

30 ml of 0.2 M NaOH is added with 50 ml "0.2 M "CH_(3)COOH solution. The extra volume of 0.2 M NaOH required to make the pH of the solution 5.00 is (10)/(x). The value of x is. The ionisation constant of CH_(3)COOH=2xx10^(-5) .

The pH of a buffer solution prepared by adding 10 mL of 0.1 M CH_(3) COOH and 20 mL 0.1 M sodium acetate will be ( given : pK_(a) of CH_(3)COOH = 4.74 )

Calculate pH of 0.05 M Acetic acid solution , if K_(a)(CH_(3)COOH) = 1.74 xx 10^(-5) .

6ml of 0.1M CH_(3)COOH when mixed with x ml of 0.1 M NaOH the pH of the resulting buffer solution was found to be 5.04 . The value of x is (log2=0.3)pK_(a(CH_(3)COOH))=4.74