How will you obtain?
Borazole from sodium borohydride (in three steps only)

Answer

To synthesize Borazole (also known as Borazine, with the formula B3N3H6) from sodium borohydride (NaBH4) in three steps, we can follow the outlined process below:

### Step 1: Formation of Trichloroborazine
1. **React Sodium Borohydride with Boron Trichloride and Ammonium Chloride**:
- Start with sodium borohydride (NaBH4) and react it with boron trichloride (BCl3) and ammonium chloride (NH4Cl).
- The reaction can be represented as:
\[ 3 \text{BCl}_3 + 3 \text{NH}_4\text{Cl} \rightarrow \text{B}_3\text{N}_3\text{H}_3\text{Cl}_3 + 3 \text{HCl} \]
- This step produces trichloroborazine (B3N3H3Cl3) along with hydrochloric acid (HCl).

### Step 2: Reduction of Trichloroborazine
2. **Treat Trichloroborazine with Sodium Borohydride**:
- Next, take the trichloroborazine (B3N3H3Cl3) and treat it with sodium borohydride (NaBH4).
- The reaction can be represented as:
\[ \text{B}_3\text{N}_3\text{H}_3\text{Cl}_3 + 6 \text{NaBH}_4 \rightarrow \text{B}_3\text{H}_6\text{N}_3 + 3 \text{NaCl} + 6 \text{H}_2 \]
- This step reduces the trichloroborazine to boron hydride (B3H6) and produces sodium chloride (NaCl) and hydrogen gas (H2).

### Step 3: Formation of Borazole
3. **React Boron Hydride with Ammonia**:
- Finally, react the boron hydride (B3H6) with excess ammonia (NH3) at high temperature.
- The reaction can be represented as:
\[ \text{B}_3\text{H}_6 + 3 \text{NH}_3 \rightarrow \text{B}_3\text{N}_3\text{H}_6 + 3 \text{H}_2 \]
- This step yields borazole (B3N3H6) and releases hydrogen gas (H2).

### Summary of Steps:
1. **Formation of Trichloroborazine**:
- React NaBH4 with BCl3 and NH4Cl.
2. **Reduction to Boron Hydride**:
- Treat B3N3H3Cl3 with NaBH4.
3. **Synthesis of Borazole**:
- React B3H6 with NH3 at high temperature.