On passing `CO_(2)` into aqueous solution containing `NaAlO_(2)`:

Options

A. `Al_(2)(CO_(3))_(3)` is formed
B. `Al(OH)_(3)` is precipitated
C. `Al_(2)O_(3)` is formed
D. collodial `Al(OH)_(3)` is formed

Explanation

To solve the problem of what happens when carbon dioxide (CO₂) is passed into an aqueous solution containing sodium aluminate (NaAlO₂), we can break down the process step by step.

### Step-by-Step Solution:

1. **Understanding the Reactants**:
- Sodium aluminate (NaAlO₂) is a compound that contains aluminum ions (Al³⁺) in solution.
- When CO₂ is introduced into the solution, it will react with water (H₂O) to form carbonic acid (H₂CO₃).

2. **Formation of Carbonic Acid**:
- The reaction of CO₂ with water can be represented as:
\[ CO_2 + H_2O \rightarrow H_2CO_3 \]

3. **Dissociation of Carbonic Acid**:
- Carbonic acid (H₂CO₃) can dissociate into bicarbonate (HCO₃⁻) and hydrogen ions (H⁺):
\[ H_2CO_3 \rightleftharpoons HCO_3^- + H^+ \]
- Further dissociation can occur, leading to the formation of carbonate ions (CO₃²⁻):
\[ HCO_3^- \rightleftharpoons CO_3^{2-} + H^+ \]

4. **Reaction with Aluminum Ions**:
- The carbonate ions (CO₃²⁻) will react with aluminum ions (Al³⁺) present in the solution. The reaction can be represented as:
\[ 3CO_3^{2-} + 2Al^{3+} + 6H_2O \rightarrow 2Al(OH)_3 \downarrow + 3CO_2 + 6H^+ \]
- This reaction leads to the formation of aluminum hydroxide (Al(OH)₃), which precipitates out of the solution.

5. **Conclusion**:
- The final product of this reaction is aluminum hydroxide (Al(OH)₃) as a precipitate. Therefore, when CO₂ is passed into an aqueous solution containing NaAlO₂, aluminum hydroxide is formed as a precipitate.

### Final Answer:
The correct answer is that Al(OH)₃ is precipitated.

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