Tin reacts with concentrated `HNO_(3)` and gives:

Options

A. stannic nitrate
B. stannous nitrate
C. metastannic acid
D. none of sigma bond

Explanation

To solve the question regarding the reaction of tin with concentrated HNO₃, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are tin (Sn) and concentrated nitric acid (HNO₃).

### Step 2: Understand the Reaction Conditions
The reaction occurs in the presence of water molecules. This is important as it can influence the products formed.

### Step 3: Write the Reaction
When tin reacts with concentrated nitric acid, it forms metastannic acid (H₂SnO₃) as one of the products. The reaction can be represented as:
\[ \text{Sn} + 4 \text{HNO}_3 \rightarrow \text{H}_2\text{SnO}_3 + 4 \text{NO}_2 + 2 \text{H}_2\text{O} \]

### Step 4: Heating the Product
When metastannic acid (H₂SnO₃) is heated, it decomposes to form tin dioxide (SnO₂) and nitrogen oxides (NO₂).

### Step 5: Conclusion
The main product of the reaction between tin and concentrated nitric acid is metastannic acid (H₂SnO₃). Therefore, the correct answer to the question is that tin reacts with concentrated HNO₃ to give metastannic acid.

### Final Answer
The product of the reaction of tin with concentrated HNO₃ is metastannic acid (H₂SnO₃).

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