Diborane reacts with water to form:

Options

A. `HBO_(2)`
B. `H_(3)BO_(3)`
C. `H_(3)BO_(3)+H_(2)`
D. `H_(2)`

Answer

To determine what diborane (B2H6) reacts with water to form, we can follow these steps:

### Step 1: Write the chemical equation for the reaction
Diborane reacts with water in a hydrolysis reaction. The chemical equation can be written as:

\[ \text{B}_2\text{H}_6 + \text{H}_2\text{O} \rightarrow \text{H}_3\text{BO}_3 + \text{H}_2 \]

### Step 2: Identify the products
From the reaction, we can see that diborane reacts with water to produce boric acid (H3BO3) and hydrogen gas (H2).

### Step 3: Balance the chemical equation
To ensure the equation is balanced, we need to make sure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation can be represented as follows:

\[ \text{B}_2\text{H}_6 + 6 \text{H}_2\text{O} \rightarrow 2 \text{H}_3\text{BO}_3 + 6 \text{H}_2 \]

### Step 4: Analyze the options
Now, we can analyze the options given in the question:
1. Metaborate
2. Boric acid
3. Boric acid plus hydrogen
4. Only hydrogen

From our balanced equation, we can see that the products of the reaction are boric acid and hydrogen gas. Therefore, the correct answer is:

**Option 3: Boric acid plus hydrogen.**