Which of following are correct.

Options

A. `B_(2)H_(6)` in non-planar.
B. `B_(2)H_(6)` undergo symmetrical cleavage with `PF_(3),CO` and `(C_(2)H_(5))_(3)N`
C. `B_(2)H_(6)` undergo unsymmetrical cleavage with `NH_(3),CH_(3)NH_(2),(CH_(3))_(2)NH`
D. `Be(2)H_(6)(s),Ga_(2)H_(6),Al_(2)H_(6)` have two type of bonds (`2C-2e` bond as well as `3C-2e` bond)

Explanation

To determine which of the statements regarding B2H6 (Diborane) are correct, we will analyze each statement based on the information provided in the video transcript.

### Step-by-Step Solution:

1. **Analyzing the Structure of B2H6**:
- The structure of B2H6 consists of two boron atoms and six hydrogen atoms.
- It has four terminal hydrogen atoms and two bridging hydrogen atoms.
- The terminal hydrogens are arranged such that two are above the plane of the boron atoms and two are below the plane.
- The bridging hydrogens connect the two boron atoms, leading to a non-planar structure.

**Hint**: Remember that the arrangement of atoms in a molecule can affect its geometry and bonding characteristics.

2. **Statement 1**: B2H6, Ga2H6, and Al2H6 have two types of bonds: two-center two-electron bonds and three-center two-electron bonds.
- This statement is correct. In diborane, there are four two-center two-electron bonds (between boron and terminal hydrogens) and two three-center two-electron bonds (involving the bridging hydrogens).
- The presence of these bond types is characteristic of compounds in group 13.

**Hint**: Identify the types of bonds in a molecule by examining how electrons are shared between atoms.

3. **Statement 2**: B2H6 undergoes symmetrical cleavage with PF3CO and triethylamine.
- This statement is also correct. B2H6 can react with larger molecules like PF3CO and triethylamine, leading to symmetrical cleavage, producing BH3 and other products.

**Hint**: Symmetrical cleavage occurs when a molecule breaks evenly, distributing the fragments equally.

4. **Statement 3**: B2H6 undergoes unsymmetrical cleavage with NH3, CH3NH2, and CH3N2NH3.
- This statement is correct as well. When B2H6 reacts with smaller amines such as NH3, it undergoes unsymmetrical cleavage, resulting in different products.

**Hint**: Unsymmetrical cleavage results in different products, often due to the size and electron-donating ability of the reactants.

5. **Conclusion**:
- All four statements regarding B2H6 are correct based on the analysis of its structure and the nature of its reactions with other compounds.

### Final Answer:
All four statements regarding B2H6 are correct.