How many of the following may react with `SiCl_(4)` to produce a non-polar product ?
`NaH, CH_(3)MgCl, H_(2)O, LiAlH_(4), H_(2)SO_(4)(l),NH_(3), Be`

Explanation

To determine how many of the given compounds react with SiCl₄ to produce a non-polar product, we will analyze each compound one by one.

### Step-by-Step Solution:

1. **NaH (Sodium Hydride)**:
- Reaction: NaH + SiCl₄ → NaCl + SiH₄
- Product: SiH₄ is a non-polar molecule.
- Conclusion: **NaH produces a non-polar product.**

2. **CH₃MgCl (Methylmagnesium Chloride)**:
- Reaction: CH₃MgCl + SiCl₄ → MgCl₂ + Si(CH₃)₄
- Product: Si(CH₃)₄ is a non-polar molecule.
- Conclusion: **CH₃MgCl produces a non-polar product.**

3. **H₂O (Water)**:
- Reaction: H₂O + SiCl₄ → H₂SiO₃ + HCl
- Products: H₂SiO₃ and HCl are both polar.
- Conclusion: **H₂O does not produce a non-polar product.**

4. **LiAlH₄ (Lithium Aluminum Hydride)**:
- Reaction: LiAlH₄ + SiCl₄ → LiCl + AlCl₃ + SiH₄
- Product: SiH₄ is a non-polar molecule.
- Conclusion: **LiAlH₄ produces a non-polar product.**

5. **H₂SO₄ (Sulfuric Acid)**:
- Reaction: H₂SO₄ does not react with SiCl₄.
- Conclusion: **H₂SO₄ does not produce any product.**

6. **NH₃ (Ammonia)**:
- Reaction: NH₃ + SiCl₄ → A polymeric substance (polar).
- Conclusion: **NH₃ does not produce a non-polar product.**

7. **Be (Beryllium)**:
- Reaction: 2Be + SiCl₄ → 2BeCl₂ + Si
- Product: Silicon (Si) is a non-polar molecule.
- Conclusion: **Be produces a non-polar product.**

### Summary of Non-Polar Products:
- Compounds that produce non-polar products: **NaH, CH₃MgCl, LiAlH₄, Be.**
- Total number of compounds producing non-polar products: **4.**

### Final Answer:
**4 compounds produce a non-polar product when reacted with SiCl₄.**

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