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First and second ionisation energies of ...

First and second ionisation energies of magnesium are `7.646 eV` and `15.035ev` respectively. The amount of energy in `kJ` needed to convert all the atoms of magnesium intp `Mg^(2+)` ions present in `12 mg` of magnesium vapour will be? [Given `1 eV = 96.5 kJ ml^(-1)]`

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To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the total ionization energy for magnesium The total ionization energy (IE_total) required to convert magnesium (Mg) into magnesium ions (Mg²⁺) is the sum of the first and second ionization energies. Given: - First ionization energy (IE₁) = 7.646 eV - Second ionization energy (IE₂) = 15.035 eV ...
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