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Following graph shows variation of ioniz...

Following graph shows variation of ionization energies with atomic number in second period `(Li -Ne)`. Value of ionization energies of `Na(11)` will be-

A

above `Ne`

B

below `Ne` but above `O`

C

below `Li`

D

between `N` and `O`.

Text Solution

Verified by Experts

`Na` is `3rd` period element and is bigger than `Li`. The distance between the nucleus and outer most electron is more as compared to `Li`. Thus the outer most electron is loosely bound with nucleus and removal of electron is easier. So option `(C )` is correct.
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