Are the oxidation state and covalency of `Be` in `[Be(H_(2)O)_(3)(OH)]^(+)` same?

Answer

To determine whether the oxidation state and covalency of beryllium (Be) in the complex \([Be(H_2O)_3(OH)]^+\) are the same, we will follow these steps:

### Step 1: Determine the Oxidation State of Beryllium
1. **Identify the components of the complex**: The complex consists of 3 water molecules (H₂O) and 1 hydroxide ion (OH⁻).
2. **Assign charges to the components**:
- Each water molecule (H₂O) has a charge of 0.
- The hydroxide ion (OH⁻) has a charge of -1.
3. **Set up the equation for the total charge**: The total charge of the complex is +1.
- Let the oxidation state of beryllium be \(x\).
- The equation can be set up as follows:
\[ x + 3(0) + (-1) = +1 \]
- Simplifying this gives:
\[ x - 1 = +1 \]
- Solving for \(x\):
\[ x = +2 \]
4. **Conclusion**: The oxidation state of beryllium in the complex is +2.

### Step 2: Determine the Covalency of Beryllium
1. **Define covalency**: Covalency refers to the total number of ligands bonded to the central atom, which in this case is beryllium.
2. **Count the ligands**:
- There are 3 water molecules and 1 hydroxide ion.
- Therefore, the total number of ligands is:
\[ 3 \text{ (from H}_2\text{O)} + 1 \text{ (from OH)} = 4 \]
3. **Conclusion**: The covalency of beryllium in the complex is 4.

### Step 3: Compare Oxidation State and Covalency
1. **Oxidation State**: +2
2. **Covalency**: 4
3. **Comparison**: The oxidation state of beryllium (+2) is not equal to its covalency (4).

### Final Conclusion
The oxidation state and covalency of beryllium in the complex \([Be(H_2O)_3(OH)]^+\) are not the same. Therefore, the answer to the question is **No**.

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