Identify the group (in Modern Peridic Table) and valency of a hypothetical elemt having atomic number 119. if group number is `x` and valency is `y`. Given the the value of `x+y`.

Explanation

To solve the question regarding the hypothetical element with atomic number 119, we will follow these steps:

### Step 1: Determine the Electronic Configuration
The atomic number 119 indicates that the element has 119 electrons. To find its electronic configuration, we start by filling the orbitals according to the Aufbau principle. The nearest noble gas before atomic number 119 is Radon (Rn), which has an atomic number of 86.

From Radon, we continue filling the orbitals:
- After Radon (Rn, 86), we fill the 5f orbitals (Actinides) and then the 6d orbitals (Transition metals).
- The next orbitals to fill are the 7s orbital.

Thus, the electronic configuration for atomic number 119 can be written as:
\[ \text{[Rn]} 5f^{14} 6d^{10} 7s^1 \]

### Step 2: Identify the Group Number
Elements in the periodic table are organized into groups based on their valence electrons. The last electron in the configuration for atomic number 119 is in the 7s orbital, specifically as \( 7s^1 \).

Since it has one electron in the outermost shell (s-block), it belongs to Group 1 of the periodic table, which consists of alkali metals.

### Step 3: Determine the Valency
The valency of an element is determined by the number of electrons in its outermost shell that can be lost, gained, or shared during chemical reactions. For alkali metals, which have one electron in their outermost shell, the valency is typically 1.

### Step 4: Assign Values to x and y
Now we can assign values based on our findings:
- Let \( x \) be the group number, which is 1.
- Let \( y \) be the valency, which is also 1.

### Step 5: Calculate x + y
Now, we can calculate \( x + y \):
\[ x + y = 1 + 1 = 2 \]

### Final Answer
The values are:
- Group number \( x = 1 \)
- Valency \( y = 1 \)
- Therefore, \( x + y = 2 \)

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