The Lathandies are characterized by the uniform `[+n]` oxidation state show by all the Lathanides. What is the value of 'n'

Explanation

To determine the value of 'n' in the context of the oxidation states of lanthanides, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Lanthanides**: The lanthanides are a series of 15 elements from lanthanum (La) to lutetium (Lu) in the periodic table. They are known for their similar properties and electronic configurations.

2. **Identify the General Electronic Configuration**: The general electronic configuration of lanthanides can be expressed as:
- Valence shell configuration: 4f^0-14 5d^0-1 6s^2
This indicates that the 6s orbital is fully filled with 2 electrons, the 5d orbital can have up to 1 electron, and the 4f orbital can have up to 14 electrons.

3. **Determine the Common Oxidation State**: The common oxidation state exhibited by lanthanides is typically +3. This is because:
- The 6s orbital contributes 2 electrons.
- The 5d orbital can contribute 1 electron.
- Therefore, when 2 electrons from the 6s and 1 electron from the 5d are removed, the total is +3.

4. **Consider the Role of the 4f Electrons**: The 4f electrons do not participate in bonding due to effective shielding by the 5s and 5p electrons. This shielding means that the 4f electrons remain in the atom and do not contribute to the oxidation state.

5. **Conclusion**: Thus, the value of 'n' in the uniform oxidation state of lanthanides is +3.

### Final Answer:
The value of 'n' is 3.

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