Highest oxidation states shown by Chromium & Maganese are `+x & +y` respectively. Give the value of `x +y`?

Explanation

To determine the highest oxidation states shown by Chromium and Manganese, we need to analyze their electronic configurations and the common oxidation states they exhibit.

### Step 1: Determine the electronic configuration of Chromium (Cr)
- Chromium has an atomic number of 24.
- The electronic configuration of Chromium is:
\[ [Ar] 3d^5 4s^1 \]
- The highest oxidation state of Chromium is +6, which occurs in compounds like CrO3.

### Step 2: Determine the electronic configuration of Manganese (Mn)
- Manganese has an atomic number of 25.
- The electronic configuration of Manganese is:
\[ [Ar] 3d^5 4s^2 \]
- The highest oxidation state of Manganese is +7, which occurs in compounds like MnO4^-.

### Step 3: Calculate the values of x and y
- Let \( x \) be the highest oxidation state of Chromium, which is +6.
- Let \( y \) be the highest oxidation state of Manganese, which is +7.

### Step 4: Find the sum \( x + y \)
- Now, we can calculate \( x + y \):
\[ x + y = 6 + 7 = 13 \]

### Final Answer:
The value of \( x + y \) is 13.

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