Which of following ions do not exist together in aqueous solution:

Options

A. `Pb^(2+),F^(-)`
B. `TI^(3+),I^(-)`
C. Both `(A)` and `(B)`
D. None of these

Explanation

To determine which ions do not exist together in aqueous solution, we need to analyze the solubility of the compounds formed by the ions in question.

### Step-by-Step Solution:

1. **Identify the Ions**: The question asks about specific ions, and we need to identify them. In this case, we are focusing on the lead ion (Pb²⁺) and the fluoride ion (F⁻).

2. **Write the Reaction**: When lead ions (Pb²⁺) are in the presence of fluoride ions (F⁻), they can react to form lead fluoride (PbF₂). The balanced chemical reaction can be written as:
\[ Pb^{2+} + 2F^{-} \rightarrow PbF_2 \]

3. **Check the Solubility of the Product**: Now, we need to determine whether lead fluoride (PbF₂) is soluble in water. Lead fluoride is known to be insoluble in aqueous solutions.

4. **Conclusion on Ion Existence**: Since PbF₂ does not dissolve in water, the ions Pb²⁺ and F⁻ cannot coexist in an aqueous solution. Therefore, they do not exist together in aqueous solution.

5. **Final Answer**: The ions that do not exist together in aqueous solution are Pb²⁺ and F⁻.