What products are formed when precipitate formed by the reaction of `Hg_(2)^(2+)` ions and excess of sodium hydroxide solution is boiled?

Explanation

To determine the products formed when the precipitate from the reaction of `Hg2^(2+)` ions and excess sodium hydroxide solution is boiled, we can follow these steps:

### Step 1: Reaction of `Hg2^(2+)` with Sodium Hydroxide
When `Hg2^(2+)` ions react with sodium hydroxide (NaOH), a precipitate of mercurous oxide (`Hg2O`) is formed. The reaction can be represented as:

\[ Hg_2^{2+} + 2 OH^- \rightarrow Hg_2O + H_2O \]
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