What happens when `Mn(II)` ions free from chloride ions react with acidified solution of `(NH_(4))_(2)S_(2)O_(8)` or `K_(2)S_(2)O_(8)` in presence of a few drops of `AgNO_(3)` solution?

Explanation

To understand what happens when `Mn(II)` ions react with an acidified solution of `(NH₄)₂S₂O₈` or `K₂S₂O₈` in the presence of a few drops of `AgNO₃`, we can break down the reaction into steps:

### Step 1: Identify the Reactants
- The reactants in this scenario are `Mn(II)` ions (Mn²⁺), the persulfate ion `(S₂O₈)²⁻` from `(NH₄)₂S₂O₈` or `K₂S₂O₈`, and `AgNO₃`.

### Step 2: Understand the Role of Persulfate Ion
- The persulfate ion `(S₂O₈)²⁻` is a strong oxidizing agent. It can oxidize `Mn(II)` ions to `Mn(VII)` ions.

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