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A substance on treatment with dilute H(2...

A substance on treatment with dilute `H_(2)SO_(4)` liberates a colourless gas which produces `(I)` turbidity with baryta water and `(ii)` turns acidified dichromate solution green. The reaction indicates the presence of `:`

A

`CO_(3)^(2-)`

B

`S^(2-)`

C

`SO_(3)^(2-)`

D

`NO_(2)^(-)`

Text Solution

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The correct Answer is:
To solve the question, we need to analyze the information provided regarding the reactions that occur when a substance is treated with dilute sulfuric acid (H₂SO₄). ### Step-by-Step Solution: 1. **Identify the Colorless Gas**: - The problem states that a colorless gas is liberated when the substance is treated with dilute H₂SO₄. Common colorless gases that can be produced in such reactions include hydrogen sulfide (H₂S), carbon dioxide (CO₂), and sulfur dioxide (SO₂). 2. **Turbidity with Baryta Water**: - The gas produced causes turbidity when it comes in contact with baryta water (barium hydroxide, Ba(OH)₂). The turbidity indicates the formation of a precipitate, which is likely barium sulfate (BaSO₄) if the gas is sulfur dioxide (SO₂). The reaction can be represented as: \[ SO_2 + Ba(OH)_2 \rightarrow BaSO_4 \downarrow + H_2O \] - Here, BaSO₄ is a white precipitate that causes turbidity. 3. **Reaction with Acidified Dichromate Solution**: - The second observation is that the gas turns acidified dichromate solution green. Potassium dichromate (K₂Cr₂O₇) contains chromium in the +6 oxidation state (orange color). When it is reduced to chromium in the +3 oxidation state, it turns green. The reaction can be represented as: \[ Cr_2O_7^{2-} + 3SO_2 + 8H^+ \rightarrow 2Cr^{3+} + 3SO_4^{2-} + 4H_2O \] - This indicates that the gas is a reducing agent, which is consistent with sulfur dioxide (SO₂). 4. **Conclusion**: - Since both reactions (formation of turbidity with baryta water and reduction of dichromate) are consistent with the presence of sulfur dioxide (SO₂), we conclude that the substance being tested indicates the presence of the sulfate ion (SO₄²⁻) in the original substance. ### Final Answer: The reaction indicates the presence of sulfate ions (SO₄²⁻).
To solve the question, we need to analyze the information provided regarding the reactions that occur when a substance is treated with dilute sulfuric acid (H₂SO₄). ### Step-by-Step Solution: 1. **Identify the Colorless Gas**: - The problem states that a colorless gas is liberated when the substance is treated with dilute H₂SO₄. Common colorless gases that can be produced in such reactions include hydrogen sulfide (H₂S), carbon dioxide (CO₂), and sulfur dioxide (SO₂). 2. **Turbidity with Baryta Water**: ...
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